<PRE><B>Question 270730</B>
Approximately 11% of people are left-handed. If two people are selected at random, what is the probability of the following events? 
A. P(Both are right-handed) = (0.89)^2
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B. P(Both are left-handed) = (0.11)^2
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C. P(One is right-handed and the other is left-handed) = 2(0.11)(0.89)
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D. P(At least one is right-handed) = 1-[P(bothleft)]]= 1-(0.11)^2
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Cheers,
Stan H. 
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