<PRE><B>Question 270692</B>
Jeffrey wrote 1 on 1 slip of paper, 2 on 2 slips of paper, 3 on 3 slips of paper, 4 on 4 slips of paper, 5 on 5 slips of paper and 6 on 6 slips of paper.lf he draws 1 slip of Paper at random, what is Probability of getting an odd number? 
---
# of ways to succeed: 1+3+5 = 9
# of possible outcomes: 1+2+3+4+5+6 = 21
---
P(odd) = 9/21 = 3/7
===============
Cheers,
Stan H.

A 1/2 b 2/5 c 3/4 d 5/6 e 3/7 
</PRE>