Question 270585
{{{23 - 2*(4 + 3*(x-1))+ 5*(x - 2*(x+3)) = 7*(x - 2*(5-(2x+3)))}}}
I hope I copied it OK. I slightly changed it to 
make it more readable to me.
You're right. It looks like a jumble to me, too, and
I'm pretty good with these things. What you have to do
to make it less of a jumble is to not look at the whole thing
at once, (like not looking down if you're climbing up a cliff)
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(a) start by identifying the innermost brackets only.
then pick just one of them and try to simplify it.
I'll start with the (2x - 3) at the end, since it is nested
inside 3 sets of brackets like this: ((( ))).
It's got a (-) in front of it, so it becomes
{{{23-2*(4+3*(x-1))+5*(x-2*(x+3)) = 7*(x-2*(5-2x-3))}}}
I got rid of the innermost ().
(b) Now I'll move on to the next set of innermost ()s
which is the (x+3) in the middle inside 2 brackets:(())
It gets multiplied by the -2 in front, so
{{{23-2*(4+3*(x-1))+5*(x-2x+6) = 7*(x-2*(5-2x-3))}}}
And I got rid of another set of ()s
Another innermost () is (x-3) moving left. It gets multiplied by 
the 3 in front:
{{{23-2*(4+3x-3)+5*(x-2x+6) = 7*(x-2*(5-2x-3))}}}
That's 3 sets of ()s I eliminated
(c) Now look for more innermost ()s.
The (5 - 2x - 3) is one. It gets multiplied by the -2 in front, so
{{{23-2*(4+3x-3)+5*(x-2x+6) = 7*(x - 10 + 4x + 6)}}}
(d) Now there are no more innermost ()s so just choose among
the brackets that are left. I'll just do them all in one step:
{{{23 - 8 - 6x + 6 + 5x - 10x + 30 = 7x - 70 + 28x + 42}}}
(e) Now just collect like terms:
{{{23 - 8 + 6 + 30 - 6x + 5x - 10x = - 70 + 42 + 7x + 28x}}}
{{{51 - 11x = -28 + 35x}}}
{{{35x + 11x = 51 + 28}}}
{{{46x = 79}}}
{{{x = 79/46}}}
This could be wrong, since it's so easy to make a mistake
along the way, but the idea is what's important. Start from 
the inside ()s and work your way out.