Question 270585
23-2[4+3(x-1)]+5[x-2(x+3)] =  7 {x-2[5-(2x+3)]  
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23-2[4+3x-3]+5[x-2x-6] =  7 {x-2[5-2x-3] 
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23-2[1+3x]+5[-x-6] =  7{x-2[2-2x]
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23-2-6x-5x-30 =  7{x-4+4x]
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-9-11x =  7{5x-4]
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-9-11x = 35x-28
46x = 19
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x = 19/46
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Cheers,
Stan H.