Question 270459
In detail steps i will show you how to  solve the equation in elimination method!
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2x+5y+13=0_2x+5=3y

Move all terms containing variables to the left-hand side of the equation.
2x+5y+13=0_2x+5-3y=0

Move all terms containing variables to the left-hand side of the equation.
2x+5y+13=0_2x-3y+5=0

Move all terms not containing a variable to the right-hand side of the equation.
2x+5y=-13_2x-3y+5=0

Move all terms not containing a variable to the right-hand side of the equation.
2x+5y=-13_2x-3y=-5

Multiply the first equation by -1 to make the coefficients of x have opposite signs.
-(2x+5y)=-(-13)_2x-3y=-5

Multiply -1 by the -13 inside the parentheses.
-(2x+5y)=13_2x-3y=-5

Multiply -1 by each term inside the parentheses.
(-2x-5y)=13_2x-3y=-5

Remove the parentheses around the expression -2x-5y.
-2x-5y=13_2x-3y=-5

Add the two equations together to eliminate x from the system.
 2x-3y=-5_<U>-2x-5y=13<u>_   -8y= 8

Divide each term in the equation by -8.
y=-1

Substitute the value found for y into the original equation to solve for x.
-2x-5(-1)=13

Multiply -5 by each term inside the parentheses.
-2x+5=13

Move all terms not containing x to the right-hand side of the equation.
-2x=8

Divide each term in the equation by -2.
x=-4

This is the final solution to the independent system of equations.
Solution: y=-1
          x=-4