Question 270420
I am a three digit odd number
100x + 10y + z
:
 my tens digit is one less than my hundreds digit
y = x-1
or
x = y+1
:
 but two more than one digit.
y = z+2
or
z = y-2
:
The sum of my digits is 20.
x + y + z = 20
Replace x and z, find y
(y+1) + y + (y-2) = 20
3y - 1 = 20
3y = 20 + 1
3y = 21
y = 7
then
x = 8
z = 5
:
The number: 875

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