Question 33437
Find the equation of the line that passes throught the given point (3, -3) and which has the slope m = 2.
The easiest way to do this is to use the "point-slope" form of the equation of a line:
{{{(y-y1) = m(x-x1)}}}

The equation of your line is:
{{{(y-(-3)) = 2(x-3)}}} Simplify.
{{{(y+3) = 2(x-3)}}} This is the equation.

If you need the "slope-intercept" form:{{{y = mx+b}}}, then, using the given slope m = 2 and the x- and y-coordinate of the given point (3, -3):

{{{-3 = 2(3) + b}}} Solve for b, the y-intercept.
{{{-3 = 6 + b}}} Subtract 6 from both sides of the equation.
{{{-9 = b}}}

The final equation, in "slope-intercept" form is:

{{{y = 2x - 9}}}