Question 270107
 In a random sample of 26 computers, the mean repair cost was $130 with a sample standard deviation of $36. Assume that the population is normally distributed. 
a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest hundredths.
E = 1.96*[36/sqrt(26)] = 13.84
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b. Find a 95% confidence interval for the population mean
CI: 130-13.84 < u < 130+13.84
CI: 116.16 < u < 143.84
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Cheers,
Stan H.