Question 269928
 If an object is propelled upward from ground level with an initial velocity of 92.5 feet per second, its height h in feet t seconds later is given by the equation h = 92.5t - 16t2. After how many seconds does the object hit the ground? Round your answer to the nearest tenth.


We need to find t when h = 0 so we have:

0 = 92.5*t - 16*t^2 

Let's rewrite this as:

16t^2 - 92.5t = 0
t*(16t - 92.5) = 0

The two solutions for this quadratic are when t = 0 and when 16t - 92.5 = 0.

t=0 is when the object is thrown so we want the value of t where

16t - 92.5 = 0
16t = 92.5
t = 92.5/16

Calculate t to the nearest tenth.