Question 33426
Every quadratic equation has at most two solutions, but for some equations, the two solutions are the same number, and for others, there is no solution on the number line (because it would involve the square root of a negative number). 

x^2+20x+____ 
In order to be a perfect square the equation should be {{{(a+b)^2}}}
But we know {{{(a+b)^2}}} = {{{a^2}}}+2*a*b+{{{b^2}}}
so comparing the equation with the standard form lets replace the values of
 a = x ;2*a*b = 20x ;we need to find b
2*a*b = 20x
b = 20x/2x = 10
so now we have a =1x; b = 10

{{{(x+10)^2}}} = {{{x^2}}}+2(1x)(10)+{{{(10)^2}}}
SO here the missing terms is 100

 x^2-3/4x+____

Applying the above procedure try to solve the second one except instead of using {{{(a+b)^2}}} use {{{(a-b)^2}}} = {{{a^2}}}-2*a*b+{{{b^2}}}
you should get the value as 9/64