Question 269827
Solve by completing the square:
{{{t^2-8t+40 = 0}}} Subtract 40 from both sides.
{{{t^2-8t = -40}}} Now add the square of half the coefficient of the t-term to both sides.  This is {{{(-8/2)^2 = 16}}}
{{{t^2-8t+16 = -40+16}}} Simplify.
{{{(t-4)^2 = -24}}} Take the square root of both sides.
{{{t-4 = sqrt(-24)}}} or {{{t-4 = -sqrt(-24)}}} Add 4 to both sides of each solution.
{{{t = 4+sqrt(-24)}}} or {{{t = 4-sqrt(-24)}}} This could be further simplified to:
{{{t = 4+2sqrt(-6)}}} or {{{t = 4-2sqrt(-6)}}}