Question 33419
Let the number be xyz. We are told that x+y+z=11


original number is xyz
--> xyz really means 100x+10y+z


Reversing gives zyx
--> zyx really means 100z+10y+x


zyx is 46 more than 5 times the old number:


So, (100z+10y+x) = 5(100x+10y+z) + 46
--> 100z+10y+x = 500x+50y+5z + 46
--> 95z-40y-499x = 46


Also, hundreds digit (x) + twice tens (y) equals units (z)
--> x + 2y = z


So, we have 3 unknowns, xy and z and we have 3 equations relating them:

x+y+z=11
95z-40y-499x = 46
x+2y=z


You try to solve these 3 :-)
answer is 137 for the number.


jon.