Question 33394
<p>Look through it to make sure I don't make a mistake myself!
 ___________________< water lvl
|..\)8 degrees
|^..\
|*A..\ 2.6              ok so submarine go down @ 8 Deg's for 2.6 miles
X........\  miles
|............\
|...............\
|_____.....\

2 FIND X, u find 90-8 to get < A (I called it *A, it means angle A).  90-8 is 82, which is < A.

 ___________________< water lvl
|\)8 degrees
|^\
|82\ 2.6             
X........\  miles
|............\
|...............\
|_____....\

Now, you just CohSahToa your way out of it.  You'll use Sine (sah, adjacent/hypotenuse).  so sin(82)=X/2.6 times 2.6 all around
sin(82)*2.6=X .  
I got 2.5746969787280828192178146550966.. rounded to 2.57.
(not 2 scale)</p>
ps:sorry, it was the best triangles i could draw..
if you dont get any of this, feel free 2 im me.