Question 269473
n = Nancy's age
r = Roger's age
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We are told:
n = 2r + 5
n + r = 32
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Viewing as a simultaneous equations:
n -2r = 5
n + r = 32
Subtracting the second equation from the first:
-3r = -27
Dividing by -3
r = 9
Roger's age is 9.
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substituting back into the sum:
n + r = 32
n + 9 = 32
n = 32 - 9
n = 23
Nancy's age is 23.
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So the sum of their ages is 32.
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But is Nancy's age 5 more than twice Roger's?
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2(9) + 5 = 23
That checks, so all we have to do is state our answer:
Nancy is 23 years old.
Roger is 9 years old.
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Done.