Question 269444
evaluate the exponential equation for three positive values of x, three negative values of x and at x=0
{{{y=3^(x-4)}}}

this is fun u get to pick ur x's
id pick (x=4,5,6)(x=-.1,-.01,-.001)(x=0) now just plug them in and solve for y
{{{y=3^(4-4)}}}
{{{y=3^(0)}}}
{{{y=1}}}
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{{{y=3^(5-4)}}}
{{{y=3^(1)}}}
{{{y=3}}}
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{{{y=3^(6-4)}}}
{{{y=3^(2)}}}
{{{y=9}}}
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so for (x=4,5,6) we have (y=1,3,9)
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{{{y=3^(-.1-4)}}}
{{{y=3^(-4.1)}}}
{{{y=0.01106121555}}}
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{{{y=3^(-.01-4)}}}
{{{y=3^(-4.01)}}}
{{{y=0.01221079017}}}
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{{{y=3^(-0.001-4)}}}
{{{y=3^(-4.001)}}}
{{{y=0.01233212334}}}
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so for (x=-.1,-.01,-.001) we have (y=0.0111,0.0122,0.0123)
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{{{y=3^(0-4)}}}
{{{y=3^(-4)}}}
{{{y=0.012345679 repeating}}}
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for x=0, y=0.012345679