Question 269198
Please help me solve this problem. 
The perimeter of triangle PQR is at least 50. If y=7, what do we know about the values of x? 
The given information is that side RQ=22, RP= 4x+2y, and PQ=18. 

The perimeter is the sum of the lengths of the 3 sides. In this case then we have:

Perimeter = 22 + 18 + (4x + 2y)
Perimeter = 22 + 18 + 4x + 2*7
Perimeter = 40 + 4x + 14
Perimeter = 54 + 4x

Since the Perimeter is at least 50 we have:

54 + 4x >= 50

4x >= 50 - 54
4x >= -4
x >= -1