Question 268184
If a triangle has a base of 8x + 16 and a height of 1/x+2, what is the area of the triangle? 

The area of a triangle is 1/2*B*H

so

{{{(1/2)(8x+16)[(1/x)+2]}}}

multiply 1/2 out

{{{(4x+8)[(1/2x)+1]}}}
Now multiply {{{(4x+8)}}} by {{{(1/2x)+1}}}

{{{4x(1/2x)+4x+8(1/2x)+8}}}

{{{4x/2x+4x+8/2x+8}}}
{{{10x+8}}}

so the area is {{{10x+8}}}