Question 269099
find two consecutive even integers whose product is 168

lET ONE NUMBER BE X

THE OTHER NUMBER WILL BE X+2

x(x+2)= 168

x^2+2x-168=0

x^2+14x-12x-168=0

x(x+14)-12(x+14)=0

(x+14)(x-12)=0

x= 12 or -14