Question 269031
the length of a rectangle is 3 in more than twice the width. the area is 189 what is the length of the rectangle?

let the width be x

length = 2x+3

x(2x+3) = 189
2x^2+3x-189=0

2x^2+-18x+21x-189=0

2x(x-9)+21(x-9)=0
(x-9)(2x+21)=0

x=9  or x= -21/2

x=9 which is the width since the width can't be negative