Question 269077
Remember that {{{x^(m/n)^""=root(n,x^m)}}}



In this case, this means that {{{16^(3/2)^""=16^(3(1/2))=(16^(1/2))^3=(sqrt(16))^3=4^3=64}}}



So {{{16^(3/2)^""=64}}}