Question 269085


<h4>x-intercept</h4>

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{2x+ y=-2}}} Start with the given equation.



{{{2x+ 0=-2}}} Plug in {{{y=0}}}.



{{{2x+ 0=-2}}} Simplify.



{{{2x=-2}}} Multiply.



{{{x=(-2)/(2)}}} Divide both sides by {{{2}}} to isolate {{{x}}}.



{{{x=-1}}} Reduce.



So the x-intercept is *[Tex \LARGE \left(-1,0\right)].



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<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{2x+ y=-2}}} Start with the given equation.



{{{2(0)+ y=-2}}} Plug in {{{x=0}}}.



{{{0+ y=-2}}} Multiply {{{2}}} and 0 to get 0.



{{{ y=-2}}} Simplify.



So the y-intercept is *[Tex \LARGE \left(0,-2\right)].



Now let's plot the points *[Tex \LARGE \left(-1,0\right)] and *[Tex \LARGE \left(0,-2\right)] which are the x and y intercepts respectively.



{{{drawing(500, 500, -5, 5, -5, 5,
grid(0),
graph(500, 500, -5, 5, -5, 5,0)
circle(-1,0,0.03),circle(-1,0,0.05),circle(-1,0,0.08),circle(-1,0,0.10),circle(-1,0,0.12),
circle(0,-2,0.03),circle(0,-2,0.05),circle(0,-2,0.08),circle(0,-2,0.10),circle(0,-2,0.12)
)}}}



Now draw a straight line through the plotted points to graph {{{2x+ y=-2}}}.



{{{ drawing(500, 500, -5, 5, -5, 5,
grid(0),
graph(500, 500, -5, 5, -5, 5,-2-2x),
circle(-1,0,0.03),circle(-1,0,0.05),circle(-1,0,0.08),circle(-1,0,0.10),circle(-1,0,0.12),
circle(0,-2,0.03),circle(0,-2,0.05),circle(0,-2,0.08),circle(0,-2,0.10),circle(0,-2,0.12)
)}}} Graph of {{{2x+ y=-2}}}