Question 268987
how do you rearrange this problem? 
(i) {{{2x + y + 1 = 0}}} 
(ii) {{{x + 3y + 3 = 0 }}}
solve (i) for y as
(iii) {{{y = -2x - 1}}}
solve (ii) for y as
(iv) {{{y = (-1/3)x - 1}}}
Now if you are to solve for x and y, we get
(0,-1)
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and this one to? 
(i) {{{2x - y - 8 = 0}}}
(ii) {{{x + 3y + 3 = 0}}}
solve (i) for y as
(ii) {{{y = 2x - 8}}}
solve (ii) for y as
(iii) {{{y = (-1/3)x - 1}}}
Now if you are to solve for x and y, we get
(3,-2)