Question 268929
Hello,
We can set up two equations and solve it. Let x be one side and y be the other side as follows:
2x+2y=34
x(y)=60 Rewrite this as: x=60/y then plug this into the first equation as:
2(60/y)+2y=34 Now multiply by y to get:
120+2y^2=34y Subtract 34y from both sides to get:
2y^2-34y+120=0 Rewrite it as:
2(y^2-17y+60)=0 factor this to get:
2(y-12)(y-5)=0 Solve for y:
y=12
y=5
Now solve for x by plugging in 12 for y:
2x+2(12)=34 
x=5
Plug in 5 to get:
x=12
So we see one side is 12 and the other side is 5.
There we go!
RJ
There is a book I wrote that might help:
www.math-unlock.com