Question 268953
(i) {{{Ma = (1/9)Mo}}}
(ii){{{ (ma + 3) = (1/5)*(mo + 3)}}}
from (i) we get
(iii) {{{9ma = Mo}}}
substitute this into (ii) we get
(iv) {{{(ma + 3) = (1/5)*(9ma + 3)}}}
distribute to get
(v) {{{(ma + 3) = (9/5)*ma + 3/5)}}}
subtract ma and subtract 3/5 to get
(vi) {{{12/5 = (4/5)ma}}}
multiply by 5 to get
(vii) {{{12 = 4ma}}}
divide by 4 to get
maria = 3
mother = 27