Question 268960
I throw a ball into the air in a movie theater. I throw it up with an initial velocity of 64 feet/sec1024ond from a balcony 10 feet high. The ceiling of the theater is 58 feet high. When will the ball hit the ceiling/
000000000000000000
Height of the ball is h(t) = -16t^2+vot+so
where vo is the initial velocity and so is the initial height.
--------------
Your Problem:
Solve 58 = -16t^2+64t+10 
Rearrange:
16t^2 - 64t + 48 = 0
---
Factor:
16(t^2-4t + 3) = 0
16(t-3)(t-1) = 0
---
Smaller positive solution:
t = 1 second
The ball will hit the ceiling in one second.
===========================================
Cheers,
Stan H.