Question 268908
perimeter of a rectangle with length l and width w is given by 2(l+w)

now given 2(l+w)=36  -------------- 1

and l=w+4        ------------------ 2

so from eq.1  l+w=18  

and substituting the value of l from eq.2 
  
 we get  w+4+w=18

 => 2w+4=18
 => 2w=14
 => w=7

so    length=11
   
      width=7