Question 33317
{{{(4x+1)/3}}} - {{{(3x-1)/2}}}= 1
taking the L.C.M
{{{(2(4x+1)-3(3x-1))/6}}}= 1
2(4x+1)-3(3x-1) = 6
8x+2-9x+3 = 6
-x+5 = 6
-x = 6-5 = 1
x = -1