Question 268838
let the ages be 

  2n-2, 2n, 2n+2  (2n-2 ---> youngest)

now given,  
                 three times the age of the youngest brother exceeds the oldest brother's age by 48 years
            
              so  3(2n-2)=2n+2+48

               => 6n-6=2n+50
               => 4n=56
               => n=14

so the age of the youngest is  2n-2 = 2*14-2 =  26

Answer:   26