Question 525
Well, first we need to assign letters to each of the numbers. x, y and z will do.

Now, if they are consecutive even numbers, then we know that x is 2 less than y, and y is 2 less than z:

{{{x = y-2}}}
{{{y = z-2}}}

We'll rearrange the second one to be consistent:

{{{z = y + 2}}}

Now for the rest of the question. The first number plus the third number is 22 less than the second number multiplied by 3:

{{{x + z = 3y - 22}}}

To work out the numbers, we will need to substitute the first 2 equations into the third, like this:

{{{(y - 2) + (y + 2) = 3y-22}}}

Expanding the brackets gives:

{{{2y = 3y-22}}}

Adding 22 to both sides, and taking away 2y from both sides:

{{{22=y}}}

So the middle number is 22. Since the other numbers are the even numbers either side of it, the final answer is:

The 3 numbers are 20, 22 and 24.