Question 268824
how do u find the area of an obtuse triangle with a base of 4,and sides of 6 and 3 cm.
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One direct method, without solving for angles, is Heron's Law.
s = 1/2 the perimeter, = (3+4+6)/2 = 6.5
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{{{Area = sqrt(s*(s-a)*(s-b)*(s-c))}}}