Question 268762
9x-6y=-12_x+2y=0

=►Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 6.
9x-6y=-12_3*(x+2y=0)

=►Multiply each equation by the value that makes the coefficients of y equal.  This value is found by dividing the least common multiple of the coefficients of y by the current coefficient.  In this case, the least common multiple is 6.
9x-6y=-12_3*(x+2y)=3(0)

=►Multiply 3 by each term inside the parentheses.
_3*(x+2y)=0

=►Multiply 3 by each term inside the parentheses.
_(3x+6y)=0

=►Remove the parentheses around the expression 3x+6y.
_3x+6y=0

=►Add the two equations together to eliminate y from the system.
3x+6y=0_<U>9x-6y=-12<u>_12x   =-12

=&#9658;Divide each term in the equation by 12.
x=-1

=&#9658;Substitute the value found for x into the original equation to solve for y.
9(-1)-6y=-12

=&#9658;Multiply 9 by each term inside the parentheses.
-9-6y=-12

=&#9658;Move all terms not containing y to the right-hand side of the equation.
-6y=-3

=&#9658;Divide each term in the equation by -6.
y=(1)/(2)

=&#9658;This is the final solution to the independent system of equations.
x=-1_y=(1)/(2)