Question 268596
Action Man was eating in a diner when his super-powered ears heard someone 2 miles away yelling for help.
 He rushed outside and ran to the man (named ED) who had fallen from a tree.
 Six minutes after he arrived, an ambulance pulled up that had driven 12 miles to the scene.
 If the ambulance drove 3 times as fast as Action Man ran, how long did it take Action Man to get to Ed?
:
Let s = A-man's speed
then
3s = Amb speed
:
Change 6 min to 6/60 = .1 hrs
:
Write a time equation: Time = dist/speed
:
A-man's time + .1 hr = Amb time 
{{{2/s}}} + .1 = {{{12/(3s)}}}
{{{2/s}}} + .1 = {{{4/s}}}; reduced fraction
multiply by s
2 + .1s = 4
.1s = 4 - 2
.1s = 2
s = {{{2/.1}}}
s = 20 mph is A-man's speed
then
{{{2/20}}} = .1 hrs which is 6 minutes for A-man to run two miles
:
:
You can confirm this by finding the time for the amb to come
3(20) = 60 mph is amb speed, would take 12 min to go 12 mi, 6 min after A-man