Question 268699
There is a point called the locator pint. It starts at (0,1)and moves from there depending on the equation. The horizontal asymptote starts at y = 0. In our case the equation moved down 1 unit. Our asymptote now is y = -1.
here is the graph
{{{ graph( 300, 200, -10, 10, -10, 10, 3*(2)^x - 1) }}}