Question 268678
{{{x^2 + 3x + 1}}}
I can try to factor it with quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
where
{{{a = 1}}}
{{{b = 3}}}
{{{c = 1}}}
{{{x = (-3 +- sqrt( 3^2-4*1*1 ))/(2*1) }}}
{{{x = (-3 +- sqrt( 9 - 4 ))/2 }}}
{{{x = (-3 +- sqrt(5))/2 }}}
solutions are:
{{{x = (-3 + sqrt(5))/2}}}
and
{{{x = (-3 - sqrt(5))/2}}}
If the factors are {{{x - a}}} and {{{x - b}}}
where {{{a}}} and {{{b}}} are the roots,
{{{x - (-3 - sqrt(5))/2}}} and
{{{x - (-3 + sqrt(5))/2}}}
are the factors of the equation