Question 268571
The first and third of three consecutive odd integers are added, the result is 69 less than five times the second integer. What is the third integer?
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Note: integer has only one "r".
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
(2x-1) + (2x+3) = 5(2x+1)-69
4x+2 = 10x-64
6x = 66
x = 11
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1st: 2x-1 = 21
2nd: 2x+1 = 23
3rd: 2x+3 = 25
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Cheers,
Stan H.