Question 268535
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Let *[tex \Large x] represent the width of the rectangle.  Let *[tex \Large l] represent the length of the rectangle.


We are given that *[tex \Large l\ =\ 2w\,+\,20].


The perimeter of a rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_{rect}\ =\ 2l\ +\ 2w]


Substitute *[tex \Large l\ =\ 2w\,+\,20] and the given perimeter:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2\left(2w\,+\,20\right)\ +\ 2w\ =\ 310] 


Now just solve for *[tex \Large w]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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