Question 33263
TOTAL FENCING=32=L+L+B+B=2(L+B)
L+B=16.......L=16-B
AREA=LB=B(16-B)=16B-B^2=-(B^2-16B)=-(B^2-2B*8+8^2-8^2)=64-(B-8)^2
(B-8)^2BENIG A PERFRC SQUARE IS ALWAYS POSITIVE.SINCE IT IS HAVING A MINUS SIGN INFRONT AREA WILL BE MAXIMUM WHEN THIS IS ZERO..THAT IS B-8=0..OR...B=8
SO L=8 AND B=8 IS THE SOLUTION WHICH GIVES MAXIMUM AREA OF 64