Question 268459
This is an RTD question. Here is a table based on the above information
person . . . . . . . rate . . . . . . . .time . . . . . . . .. distance
russ . . . . . . . . . . 7 . . . . . . . . . .y . . . . . . . . . . . 7y
janet . . . . . . . . . 5. . . . . . . . . . y. . . . . . . . . . . 5y
total . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .(1/2)
FRom column 3, we get
7y + 5y = 1/2
12y = 1/2
y = 1/24
1/24 hrs or ~ 2.5 minutes