<PRE><B>Question 33270</B>
Let the length and width of rectangle be L and W 
given:
L = W+8
Area = 20 sq inches
But area = L*W
20 = L*W
20 =(8+W)*W
20 = 8W+{{{W^2}}}
{{{W^2}}}+8W -20 = 0
{{{W^2}}}+10W - 2W -20 = 0
W(W+10)-2(W+10) = 0
(W-2)(W+10) = 0
W - 2 = 0 or W +10 = 0
W = 2 or W = -10 which cannot be as it is a negative value
so W = 2In
L = 2+8 = 10 in
SO length of rectangle is 10 in



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