Question 268141
<font face="Garamond" size="+2">


Let *[tex \Large r] represent the rate of the slower bus.  Then the rate of the faster bus must be *[tex \Large r\ +\ 5].


Since the two buses are traveling in opposite directions, the total rate is the sum of the rates of the two vehicles, namely:  *[tex \Large r\ +\ r\ +\ 5], or *[tex \Large 2r\ +\ 5]


Since distance equals rate times time:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 375\ =\ 3(2r\ +\ 5)]


Solve for *[tex \Large r].  The distance traveled by the slower bus is *[tex \Large 3r].  The distance traveled by the faster bus is *[tex \Large 3(r + 5)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>