Question 268141
speed of slower bus  = {{{s}}}
speed of faster bus = {{{s + 5}}}
They are moving apart at their combined speeds, which are:
{{{s + s + 5}}}
Let {{{d[1]}}} = distance slower bus has gone in mi
Let {{{d[2]}}} = distance faster bus has gone in mi
{{{d[1] + d[2] = 375}}} mi
Since {{{d = r*t}}}
{{{375 = (s + s + 5)*3}}}
{{{375 = 6s + 15}}}
{{{6s = 360}}}
{{{s = 60}}}
{{{s + 5 = 65}}}
{{{d[1] = 60*3}}}
{{{d[1] = 180}}} mi
{{{d[2] = 65*3}}}
{{{d[2] = 195}}} mi
The slower bus went 180 mi, the faster went 195 mi
check answer:
{{{375 = 6s + 15}}}
{{{375 = 6*60 + 15}}}
{{{375 = 360 + 15}}}
{{{375 = 375}}}
OK