<PRE><B>Question 268020</B>
A bartender has rum that is 40% alcohol. How much rum and how much cola need to be mixed together to make 5 liters of rum-and-cola that is 16% alcohol? 
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Equation:
alcohol + alcohol = alcohol
0.40x + 0(5-x) = 0.16*5
Multiply thru by 100 to get:
40x = 16*5
x = 80/40 = 2 liters (amt. of rum needed in the mixture
5-x = 3 liters (amt. of cola needed in the mixture)
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Cheers,
Stan H.</PRE>