Question 33260
[{{{(x)^2}}} - 3x -10]/[{{{(x)^2}}} - x -20]
factorizing numerator:
[{{{(x)^2}}} - 3x -10]
{{{(x)^2}}}-5x +2x -10
x(x-5)+2(x-5)
(x+2)(x-5)
factorizing denominator
[{{{(x)^2}}}-x-20]
[{{{(x)^2}}}-5x+4x-20]
x(x-5)+4(x-5)
(x+4)(x-5)
therfore the given given expression can be written as
{{{(x+2)(x-5)}}}/{{{(x+4)(x-5)}}}
cancelling (x-5) in both numerator and denominator we get
{{{(x+2)/(x+4)}}}