Question 267876
how do you get the quotient for 
-9/i in the form a + bi 
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Multiply numerator and denominator by "i" to get:
-9i/(-1)
= 9i
= 0+9i
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and 
how do you get the quotient for 

(9+3i)/(4 -8i)
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Multiply numerator and denominator by 4+8i to get:
[(4+8i)(9+3i)]/[16+64]
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= [36-24+72i+12i]/80
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= [12+84i]/80
Reduce to get:
= [3 + 21i]/20
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Cheers,
Stan H.