<PRE><B>Question 267481</B>
x/(.900-2x)^2 = 4 How do I solve for x?
:
Assume the problem is:
{{{x/(.900-2x)^2}}} = 4 
FOIL
{{{x/(.81 - 1.8x - 1.8x + 4x^2)}}} = 4
:
{{{x/(4x^2-3.6x+.81)}}} = 4 
:
x = 4(4x^2 - 3.6x + .81)
:
x = 16x^2 - 14.4x + 3.24
:
0 = 16x^2 - 14.4x - x + 3.24
:
16x^2 - 15.4x + 3.24 = 0
:
Solve this using the quadratic formula
Two solutions: x~.652 and x~.311
;
Check both of these in the original equation</PRE>