Question 267796
Let the total number of tables to be made = x
According to a contract, a factory should make 48 tables each day.
The number of days = x/48  ..(1)
But the factory made 50 tables for [(x/48)-3] days and made 100 tables in the last three days.
Total number of tables is [(x/48)-3]*50+100 = x
                          [(x-144)/48]*50 = x-100
                          [x-144]*50 = 48(x-100)
                          50x-7200 = 48x-4800
                          50x-48x = 7200-4800
                          2x = 2400
                          x = 2400/2
                          x = 1200