Question 267797
Given, a=5, b=8 and c=10
Let s = (a+b+c)/2
    s = (5+8+10)/2 = 11.5
Area of the triangle = Sqrt[s(s-a)(s-b)(s-c)]
                     = Sqrt[11.5*(11.5-5)(11.5-8)(11.5-10)
                     = Sqrt [ 11.5*6.5*3.5*1.5]
                     = 19.81