Question 267798
suppose a factory contains two machines. there is a 19 % probability that the first machine will break down and a 22 % chance the second machine breaks down. the two machines are independent.
A. probability both machines break down = (0.19)(0.22)
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B. probability AT LEAST one machine breaks down = 1-(p(neither breaks down)
= 1 - [0.81*0.78]
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C. probability that only one breaks down = 1 - P[both break down]-P[neither
breaks down] = 1 - (ans. to A)- 0.81*0.78
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Cheers,
Stan H.
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A. Pr (A and B) = .0418
B. ?
C. ?