Question 267783
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ -\ 3y\ =\ 9]


Yes, if you use 0 for *[tex \Large x] then you get -3 for *[tex \Large y], but that would mean that the point is (0,-3), not (0,3).


So, substitute 3 for *[tex \Large x]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4(3)\ -\ 3y\ =\ 9]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 1]


So not (3,7)


Substitute 2:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4(2)\ -\ 3y\ =\ 9]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ -\frac{1}{3}]


Ta da!!


If the third one is correct, then the last one can't be because the last two ordered pairs have the same *[tex \Large x] coordinate and different *[tex \Large y] coordinates.  Only one of the last two points could possibly be on the line.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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