Question 267713
3x+y=16 
y=16-3x
---------- Are these the 2 equations?  It's the same one twice.
There's no point in working further.
--> dependent, infinite # of solutions.
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x(16-3x)=16x-3x^2 ??  Where did this come from?

x^2 +(16x-3x^2)= x^2+16x+9x^2 
10x^2 +256 
I get 10x^2-144x+256........the answer is 10x^2-96x+256 
How do they get -96x??
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Restate the problem, if it's different than that above.